Q.
Consider the reactions :-
Identify $A, X, Y$ and $Z$
Solution:
Since 'A' gives positive silver mirror test therefore, it must be an aldehyde or $\alpha$
Hydroxyketone.
Reaction with semicarbazide indicates that A can be an aldehyde or ketone.
Reaction with $OH ^{-}$ i.e., aldol condensation (by assuming alkali to be dilute) indicates that $A$ is aldehyde as aldol reaction of ketones is reversible and carried out in special apparatus.
These indicates option (2).
$\underset{(X)}{CH _{3}- CH _{2} OH}\xrightarrow[{573\,K}]{{Cu}} \underset{(A)}{CH_3 -CHO} \xrightarrow[{\Delta}]{(Ag(NH_3)_2)^+,OH^-} CH_3 -COOH$
