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Q. Consider the reactions given below. On the basis of these reactions find out which of the algebric relations given in options $(a)$ to $(d)$ is correct?
(i) $C_{\left(g\right)}+4H_{\left(g\right)} \to CH_{4\left(g\right)}; \Delta_{r}H = x\,kJ\,mol^{-1}$
(ii) $C_{\left(graphite,\,s\right)}+2H_{2\left(g\right)} \to CH_{4\left(g\right)}; \Delta_{r}H = y\,kJ\,mol^{-1}$

Thermodynamics

Solution:

In eqn $(i)$, no bond is being broken while in eqn $(ii)$, $2\, H-H$ bonds are broken. So, in eqn $(ii)$ some of the energy is used up to break the bonds. Thus, $x > y$.