1. Tardigrade
  2. Question
  3. Chemistry
  4. Consider the reaction: 4 NO 2( g )+ O 2( g ) arrow 2 N 2 O 5( g ) Δr H =-111 kJ If N 2 O 5( s ) is formed instead of N 2 O 5( g ) in the above reaction, the Δr H value will be: (given, Δ H of sublimation for N 2 O 5 is 54 kJ mol -1 )

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Q. Consider the reaction :
$4 NO _{2}( g )+ O _{2}( g ) \rightarrow 2 N _{2} O _{5}( g )$
$\Delta_{r} H =-111 kJ$
If $N _{2} O _{5}( s )$ is formed instead of $N _{2} O _{5}( g )$ in the above reaction, the $\Delta_{r} H$ value will be :
(given, $\Delta H$ of sublimation for $N _{2} O _{5}$ is $54 kJ mol ^{-1}$ )

AIEEEAIEEE 2011Thermodynamics

Solution:

$- 111 - 54 = \Delta H'$
$\Delta H' =- 165 \,KJ$

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