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Q. Consider the parabola $y^2 = 4x$. Let $P$ and $Q$ be points on the parabola where $P. (4, -4)$ & $Q (9, 6)$. Let $R$ be a point on the arc of the parabola between $P \& Q$. Then the area of $\Delta $PQR is largest when

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Solution:

Equation of $PQ$ is $2x - y = 12$
image
Perpendicular distance
$L R=\left|\frac{2 t^{2}-2 t-12}{\sqrt{5}}\right|$
$=\frac{2}{\sqrt{5}}(t-3)(t+2)$
$L R$ is Maximum, at $t=\frac{1}{2}$
$\therefore R$ is $\left(\frac{1}{4}, 1\right)$