Question

Consider the nuclear reaction $x^{200} \rightarrow A^{110}+$ $B^{90}.$ If the binding energies per nucleon for X, A and B are 7.4MeV, 8.2MeV and 8.2MeV respectively, in the nuclear reaction the energy released is

• A. $200MeV$
• B. $160MeV$
• C. $110MeV$
• D. $90MeV$

Answer 1

Answer: (B)

$X^{200} \rightarrow A^{110}+B^{90}$
$\left(\right.BE\left(\left.\right)_{\text{protucts}}=\left(\right.110+90\left.\right)\times 8.2=1640MeV$
$\left(\right.BE\left.\right)$ reac tan $ts=200\times 7.4=1480MeV$
$\Rightarrow $ Energy released
$\left(\right.1640-1480\left.\right)=160MeV$