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  4. ln (k2/k1) = - (Ea/R) ( (1/T2) - (1/T1) ) Consider the following statements: 1. increase in concentration of reactant increases the rate of a zero order reaction 2. rate constant k is equal to collision frequency A if Ea = 0. 3. rate constant k is equal to collision frequency A if Ea = ∞ 4. In k vs T is a straight line 5. In k vs 1/T is a straight line Correct statements are

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Q. $ln \frac{k_2}{k_1} = - \frac{E_a}{R} \bigg( \frac{1}{T_2} - \frac{1}{T_1} \bigg) $Consider the following statements :
$1$. increase in concentration of reactant increases the rate of a zero order reaction
$2$. rate constant $k$ is equal to collision frequency $A$ if $E_a = 0$.
$3$. rate constant $k$ is equal to collision frequency $A$ if $E_a = \infty$
$4$. In $k\, vs\, T$ is a straight line
$5$. In $k\, vs\, 1/T$ is a straight line
Correct statements are

KEAMKEAM 2010Chemical Kinetics

Solution:

Correct answer is (b) $2$ and $5$