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Q. Consider the following sequence of reaction
$Ph - NO _2 \xrightarrow{ Sn / HCl } X \xrightarrow{ NaNO _2 / HCl } C \xrightarrow{ CuBr / HBr } Q$
The final product $(Q)$ is

NTA AbhyasNTA Abhyas 2020Amines

Solution:

$Ph-NO_{2}\overset{S n / H C l}{ \rightarrow }Ph-NH_{2}\overset{N a N O_{2} / H C l}{ \rightarrow }$

$Ph-N=N-Cl\overset{C u B r / H B r}{ \rightarrow }Ph-Br$