Question

Consider the following relations for emf of a electrochemical cell :
(a) emf of cell = (Oxidation potential of anode) - (Reduction potential of cathode)
(b) emf of cell = (Oxidation potential of anode) + (Reduction potential of cathod)
(c) emf of cell = (Reduction potential of anode) + (Reduction potential of cathode)
(d) emf of cell = (Oxidation potential of anode) - (Oxidation potential of cathode)
Which of the above relations are correct ?

• A. (a) and (b)
• B. (c) and (d)
• C. (b) and (d)
• D. (c) and (a)

Answer 1

Answer: (C)

${{E}_{cell}}={{E}^{o}}_{_{(red)}^{cathode}}-{{E}^{o}}_{_{(red)}^{anode}}$
or
${{E}_{cell}}={{E}^{o}}_{_{(red)}^{cathode}}+{{E}^{o}}_{_{(oxid)}^{Anode}}$
or
${{E}_{cell}}={{E}^{o}}_{_{(oxid)}^{anode}}-{{E}^{o}}_{_{(oxid)}^{cathode}}$