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  4. Consider the following reaction, CCl 3 CH = CH 2 xrightarrow[H2O2/HOCl] NaBO 4 Product (P) P is

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Q. Consider the following reaction, $CCl _{3} CH = CH _{2} \xrightarrow[H_2O_2/HOCl]{ NaBO _{4}}$ Product $(P) P$ is

Bihar CECEBihar CECE 2015

Solution:

Since, $ CC{{l}_{3}} $ is an electron withdrawing group Thus, product$ P$ is
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