1. Tardigrade
  2. Question
  3. Chemistry
  4. Consider the following experiments and answer the questions at the end of it (A) When Fe ( CN )2 solution is treated with KCN solution, species formed, no longer, gives tests ofFe 2+ and CN - (B) When K 2 SO 4 solution is treated with Al 2( SO 4)3 solution, species formed give tests of K +, Al 3+ and SO 42- Species formed in experiment A does not give test ofFe 2+ and CN -. It is due to formation of

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Q. Consider the following experiments and answer the questions at the end of it
(A) When $Fe ( CN )_2$ solution is treated with KCN solution, species formed, no longer, gives tests ofFe ${ }^{2+}$ and $CN ^{-}$
(B) When $K _2 SO _4$ solution is treated with $Al _2\left( SO _4\right)_3$ solution, species formed give tests of $K ^{+}, Al ^{3+}$ and $SO _4^{2-}$
Species formed in experiment $A$ does not give test ofFe ${ }^{2+}$ and $CN { }^{-}$. It is due to formation of

Coordination Compounds

Solution:

Correct answer is (d) $K _4\left[ Fe ( CN )_6\right]$