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Q. Consider the following equilibrium in a closed container
$N _{2} O _{4}(g) \rightleftharpoons 2 NO _{2}(g)$
At a fixed temperature, the volume of the reaction container is halved. For this change, which of the following statements hold true regarding the equilibrium constant $\left(K_{p}\right)$ and degree of dissociation $(\alpha)$ ?

IIT JEEIIT JEE 2002Equilibrium

Solution:

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At constant temperature, having the volume will change both $p$ and $\alpha$ but $K_{p}$ remains constant.