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Q. Consider the following electronic configuration of an element (P) :
$[ Xe ] 4 f ^{14} 5 d ^{1} 6 s ^{2}$
Then correct statement about element ‘P’ is:

JIPMERJIPMER 2019

Solution:

$\left[\right.$ Xe $44 f^{14} 5 d^{1} 6 s^{2}$
Atomic number = 71; Period number = 6th; Group number = 3rd