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Q. Consider the equation $\frac{ d }{ dt }\left(\int \overrightarrow{ F } \cdot d \overrightarrow{ S }\right)= A (\overrightarrow{ F } \cdot \overrightarrow{ p })$ where $\overrightarrow{ F }=$ force, $\overrightarrow{ s }=$ displacement, $t =$ time and $\overrightarrow{ p }=$ momentum. The dimensional formula of $A$ will be

Physical World, Units and Measurements

Solution:

$\left[\frac{ d }{ dt }\left(\int \overrightarrow{ F } \cdot d \overrightarrow{ S }\right)\right]$
$=[ A (\overrightarrow{ F } \cdot \overrightarrow{ p })]$
$\Rightarrow \left[\frac{ Fs }{ t }\right]=[ AFp ]$
$\Rightarrow [ A ]=\left[\frac{ s }{ pt }\right]$
$=\frac{ L }{ MLT ^{-1} \times T }= M ^{-1}$