Q.
Consider the circuit given below
Choose the sketch depicting the output Y of this circuit having inputs A and B as given below
TS EAMCET 2018
Solution:
Truth table for the given diagram
A
B
A.B
Y
0
0
1
0
1
0
1
0
0
1
1
0
1
1
0
1
From 0 to $t_{1}$
$A=1, B=1, \text { so } Y=1$
From $t_{1}$ to $t_{2}$
$A=0, B=0, \text { so } Y=0$
From $t_{2}$ to $t_{3}$
$A=1, B=0, \text { so } Y=0$
From $t_{3}$ to $t_{4}$
$A=0, B=1, \text { so } Y=0$
From $t_{4}$ to $t_{5}$
$A=1, B=1, \text { so } Y=1$
From $t_{5}$ to $t_{6}$
$A=0, B=0, \text { so } Y=0$
| A | B | A.B | Y |
| 0 | 0 | 1 | 0 |
| 1 | 0 | 1 | 0 |
| 0 | 1 | 1 | 0 |
| 1 | 1 | 0 | 1 |