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Q. Consider oxoacids of $N , S$ and $Cl$.
(I) $HNO _{2}, HNO _{3}, H _{2} N _{2} O _{2}$
(II) $H _{2} SO _{3}, H _{2} SO _{4}, H _{2} S _{2} O _{3}$
(III) $HCIO , HCIO _{2}, HCIO _{3}, HCIO _{4}$
Strongest acid in each case is
(I) (II) (III)
(a) $HNO_3$ $H_2SO_4$ $HClO_4$
(b) $H_2N_2O_2$ $H_2S_2O_3$ $HClO$
(c) $HNO_3$ $H_2SO_3$ $HClO_3$
(d) $HNO_3$ $H_2SO_3$ $HClO_3$

Equilibrium

Solution:

Greater the oxidation number of the central atom, stronger is the acid

(I) $\underset{+3}{HNO_2} \, \underset{+5}{HNO_{3}}\, \underset{+1}{H_2N_2O_{2}}$

(II) $\underset{+4}{H_2 SO_{3}}\, \underset{+6}{H_2 SO_{4}}\, \underset{+2}{H_2S_2O_{3}}$

(III) $\underset{+1}{HCl}\, \underset{+3}{HClO_{2}}\, \underset{+5}{HClO_{3}}\, \underset{+7}{HClO_{4}}$

In $(I) : HNO _{3}( II ): H _{2} SO _{4}( III ): HClO _{4}$