Question

Consider $f:(-\infty, 0) \cup\left(\frac{1}{3 e}, \infty\right) \rightarrow R$, defined by $f(x)=\frac{3 x}{2} \ln \left(e-\frac{1}{3 x}\right)$ then

• A. $ f(x)$ has no point of inflection.
• B. $ f(x)$ is surjective but not injective.
• C. $f(x)$ is bijective function.
• D. $f(x)=\frac{-1}{2 e}$ has two distinct solutions.

Answer 1

Answer: (A), (B), (D)

Correct answer is (a) $ f(x)$ has no point of inflection.Correct answer is (b) $ f(x)$ is surjective but not injective.Correct answer is (d) $f(x)=\frac{-1}{2 e}$ has two distinct solutions.