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  4. Consider a Zener diode connected in reverse bias with a 15 V battery and a 10 kΩ resistor in series. If the breakdown voltage of the diode is 4.5 V , then find the current flowing through the Zener in μA :

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Q. Consider a Zener diode connected in reverse bias with a $15\,V$ battery and a $10\,k\Omega $ resistor in series. If the breakdown voltage of the diode is $4.5\,V$ , then find the current flowing through the Zener in $μA$ :

NTA AbhyasNTA Abhyas 2022

Solution:

$I=\frac{V_{\text{in }} - V_{z}}{R_{s}}$
$=\frac{15 - 4 . 5}{10 \times 10^{3}}$
$=\frac{10 . 5}{10^{4}}$
$=1.05\times 10^{- 3}A$
$\therefore I=1.05\,mA=105\,μA$