Question

Consider a Young's double slit experiment as shown in figure. What should be the slit separation d in terms of wavelength $\lambda$ such that the first minima occurs directly in front of the slit $(S_1)$ ?

• A. $\frac{\lambda}{2\left(5-\sqrt{2}\right)}$
• B. $\frac{\lambda}{\left(5-\sqrt{2}\right)}$
• C. $\frac{\lambda}{\left(\sqrt{5}- 2\right)}$
• D. $\frac{\lambda}{ 2\left(\sqrt{5}- 2\right)}$

Answer 1

Answer: (D)

$\sqrt{5} d -2d = \frac{\lambda}{2}$