1. Tardigrade
  2. Question
  3. Mathematics
  4. Consider a single throw of die and two events. A = the number is even = 2,4,6 B = the number is a multiple of 3= 3,6 Assertion: P ( A ∪ B )=(4/6)=(2/3) and P ( A ∩ B )=(1/6) Reason: P ( overline A ∩ overline B )= P ( overline A ∪ B )=1-(2/3)=(1/3)

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Q. Consider a single throw of die and two events.
$A =$ the number is even $=\{2,4,6\}$
$B =$ the number is a multiple of $3=\{3,6\}$
Assertion : $P ( A \cup B )=\frac{4}{6}=\frac{2}{3}$ and $P ( A \cap B )=\frac{1}{6}$
Reason : $P (\overline{ A } \cap \overline{ B })= P (\overline{ A \cup B })=1-\frac{2}{3}=\frac{1}{3}$

Probability

Solution:

Both Assertion and Reason are correct but Reason is not the correct explanation.