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Q. Consider a region in free space bounded by the surfaces of an imaginary cube having sides of length ‘$a$’ as shown in the diagram. A charge $+Q$ is placed at the centre ‘$O$’ of the cube. $P$ is such a point outside the cube that the line $OP$ perpendicularly intersects the surface $ABCD$ at $R$ and also $OR = RP = a/2$. A charge $+Q$ is placed at point $P$ also. What is the total electric flux through the five faces of the cube other than $ABCD$ ?Physics Question Image

WBJEEWBJEE 2018Electric Charges and Fields

Solution:

For surface $A B C D$ electric flux is zero. Because at surface $A B C D$ net electric field is zero. Using Gauss's law,
$\oint \Sigma \cdot d S=\frac{Q_{\text {in }}}{\varepsilon_{0}}$
Electric flux through the five faces of the cube,
$\phi_{B}=\frac{Q}{\varepsilon_{0}}$