1. Tardigrade
  2. Question
  3. Chemistry
  4. Consider a reaction A(g)→3B(g)+2C(g)with rate constant is 1.386 × 10-2 min-1 in a non-rigid closed container starting with 2 moles of A in 12.5 L vessel initially, if reaction is allowed to take place at constant pressure and at 298 K the conc, of B after 100 min is

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Q. Consider a reaction $A\left(g\right)\to3B\left(g\right)+2C\left(g\right)$with rate constant is $1.386 \times 10^{-2} min^{-1}$ in a non-rigid closed container starting with $2$ moles of $A$ in $12.5\, L$ vessel initially, if reaction is allowed to take place at constant pressure and at $298 K$ the conc, of $B$ after $100 \,min$ is

Chemical Kinetics

Solution:

$A\to3B+2C$
$K=\frac{2.303}{t}log \frac{\left[A\right]_{0}}{\left[A\right]}\Rightarrow \left[A\right]=0.0016$
$.0016=\frac{n_{A}}{Vol}$
$.0016\times12.5=n_{A}$
$n_{A}=.02$
$x_A$ decomposed $= 2 - 0.02 = 1.98$
Moles of $A$ decomposed $= 1.98$
So moles of $B$ formed $= 5.94$
Assuming $n\propto v$ final $vol. = 62 L$
So find cone, of $B=\frac{5.94}{62}=0.09\, mol/L$