Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Consider a line pair $2 x^2+3 x y-2 y^2-10 x+15 y-28=0$ and another line $L$ passing through origin with gradient 3. The line pair and line $L$ form a triangle whose vertices are $A , B$ and $C$.
Sum of the contangents of the interior angles of the triangle $ABC$ is

Straight Lines

Solution:

The two lines are
$(2 x - y +4)( x +2 y -7)=0 $
$\text { Line Lis } $
$y = 3x$
$ \angle B =90^{\circ} $
$\therefore \cot B =0$
$ \cot A =\frac{21 \times \sqrt{5}}{\sqrt{5} \times 3}=7$
image
$ \cot C=\frac{3 \times \sqrt{5}}{\sqrt{5} \times 21}=\frac{1}{7} $
$\therefore \text { sum of cotangents }=7+\frac{1}{7}=\frac{50}{7}$