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  4. Compound A on reduction gives B which on further reaction with CHCl3 and alcoholic KOH gives compound C which on further hydrolysis gives aniline. The compound A is :

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Q. Compound A on reduction gives B which on further reaction with $CHCl_3$ and alcoholic $KOH$ gives compound C which on further hydrolysis gives aniline. The compound A is :

Amines

Solution:

$C_{6}H_{5}NO_{2} \xrightarrow[{Sn/HCl}] { \text{Red}} C_{6}H_{5}NH_{2} \xrightarrow[{CHCl_{3}}] {KOH} C_{6}H_{5}NC \xrightarrow[{Boil}]{H_{2}O} C_{6}H_{5}NH_{2}+HCOOH$