Question

Compound $'A'$ of molecular formula $C_4H_{10}O$ on treatment with Lucas reagent at room temperature gives compound $'B'$. When compound $'B'$ is heated with alcoholic $KOH$, it gives isobutene. Compound $'A'$ and $'B'$ are respectively

• A. $2$-methyl-$2$-propanol and $2$-methyl-$2$-chloropropane
• B. $2$-methyl-$1$-propanol and $1$-chloro-$2$-methylpropane
• C. $2$-methyl-$1$-propanol and $2$-methyl-$2$-chloropropane
• D. butan-$2$-ol and $2$-chlorobutane
• E. butan-$1$-ol and $1$-chlorobutane

Answer 1

Answer: (A)

Correct answer is (a) $2$-methyl-$2$-propanol and $2$-methyl-$2$-chloropropane