1. Tardigrade
  2. Question
  3. Chemistry
  4. Compound A (molecular formula C3H8O) is treated with acidified potassium dichromate to form a product B (molecular formula C3H6O). B forms a shining silver mirror on warming with ammoniacal silver nitrate. B when treated with an aqueous solution of H2 NCONHNH2. HCl and sodium acetate gives a product C. Identify the structure of C.

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Q. Compound A (molecular formula $C_3H_8O)$ is treated with acidified potassium dichromate to form a product $B$ (molecular formula $C_3H_6O)$. $B$ forms a shining silver mirror on warming with ammoniacal silver nitrate. $B$ when treated with an aqueous solution of $H_2 NCONHNH_2. HCl$ and sodium acetate gives a product $C$. Identify the structure of $C$.

AIIMSAIIMS 2010Aldehydes Ketones and Carboxylic Acids

Solution:

Reaction of B indicates that B is an aldehyde thus B should be $C_2H_5CHO $ or $CH_3CH_2CHO $ and therefore C should be $CH_3CH_2CH = NNHCONH_2. $

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