Question

Complete the reactions with appropriate products.
$(i) CH_{3}CHO + NH_{2}OH \to X$
$(ii) CH_{2} = CH_{2} + PdCl_{2} +H_{2}O \xrightarrow{CuCl_{2}}Y$
$(iii) CH_{3}CH_{2}CH_{2}CH_{2}OH \xrightarrow{CrO_{3} - H_{2}SO_{4}} Z$

• A. $X = CH_{3}CH = NOH, Y = CH_{3}CHO, Z = CH_{3}CH_{2}CH_{2}COOH$
• B. $X = CH_{3}CH_{2}NH_{2}, Y = CH_{3}CH_{2}CHO, Z=CH_{3}CH_{2}CH_{2}COOH$
• C. $X = CH_{3}CONH_{2}, Y = HCHO, Z = CH_{3}COCH_{3}$
• D. $X = CH_{3}C \equiv N, Y = CH_{3}CHO,Z = HCOOH$

Answer 1

Answer: (A)

When butanol undergo reaction with $CrO _{3}- H _{2} SO _{4}$ in presence of sulphuric acid, it poroduce batanoic acid.
Hence, the products are
$X \rightarrow CH _{3}= NOH $
$Y \rightarrow CH _{3}- CHO$
$Z \rightarrow CH _{3} CH _{2} CH _{2} COOH$