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Q. Complete the following reaction by identifying $X$ and $Y$.
$CH_3CH_2C \equiv CH \xrightarrow{NaNH_2} X\xrightarrow{C_2H_5Br} Y$

Hydrocarbons

Solution:

1-Butyne on reaction with $C _{2} H _{5} Br$ in the presence of $NaNH _{2}$ forms hex-3-yne.
$CH _{3} CH _{2}- C \equiv CH \xrightarrow{ NaNH _{2}}CH _{3} CH _{2}-\underset{(X)}{ C } \equiv C ^{-} Na ^{+} \xrightarrow{ C _{2} H _{5} Br }$
$CH _{3} CH _{2}- \underset{(Y)}{C \equiv C} - CH _{2} CH _{3}$