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  4. Complete combustion of 3 g of ethane gives x × 1022 molecules of water. The value of x is (Round off to the Nearest Integer). [Use: N A =6.023 × 1023; Atomic masses in u: C: 12.0 ; O: 16.0 ; H: 1.0]

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Q. Complete combustion of $3\, g$ of ethane gives $x \times 10^{22}$ molecules of water. The value of $x$ is (Round off to the Nearest Integer).
[Use : $N _{ A }=6.023 \times 10^{23}$; Atomic masses in $u : C : 12.0 ;\, O : 16.0 ;\, H : 1.0$]

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Solution:

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No. of molecules $=0.3 \times 6.023 \times 10^{23}$

$=18.069 \times 10^{22}$