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Q. Compare bond angles for the following molecules

Question

NTA AbhyasNTA Abhyas 2020Chemical Bonding and Molecular Structure

Solution:

$\text{Bond} \, \text{angle} \propto \frac{\text{1}}{\text{electronegativity} \, \text{of} \, \text{surrounding} \, \text{atom}}$

As Electronegativity of F is higher than that of H, hence x > y.