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  4. Commercial 11.2 volume H2O2 solution has a molarity of

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Q. Commercial $11.2$ volume $H_2O_2$ solution has a molarity of

Hydrogen

Solution:

$10$Vol. $H_2O_2 = 3.035\,g\,H_2O_2$
$\therefore 11.2$ vol. $H_2O_2 = \frac{3.035\times 11.2}{10} = 33.99\,g$
molarity $= \frac{\text{Strength}}{\text{mol.wt}} = \frac{33.09}{34} = 1\,M$