Cold $FeSO _{4}$ solution on absorption of NO develops brown colour due to the formation of $\left[ Fe \left( H _{2} O \right)_{5}( NO )\right] SO _{4}$.
$FeSO _{4}+ NO +5 H _{2} O \longrightarrow \underset{\text{Brown ring complex}}{\left[ Fe \left( H _{2} O \right)_{5}( NO )\right] SO _{4}}$
This complex has $3.89\, BM$ magnetic moment shows that it has 3 unpaired electrons.