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Q. Coefficient of kinetic friction between $3\,kg$ and $2\,kg$ block is $0.25$ . The horizontal table surface is smooth. Find the acceleration (in S.I unit) of the block of mass $10\,kg$ .
Question

NTA AbhyasNTA Abhyas 2022

Solution:

$100-T_{2}=10a$
$T_{2}-T_{1}-0.25\times 20=3a$
$T_{1}-0.25\times 20=2a$
Adding the above three equations and solving for acceleration we get
$a=\frac{100 - 0.25 \times 20 - 0.25 \times 20}{15}=6\,ms^{- 2}$