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  4. Cl2 reacts with CS2 in presence of I2 catalyst to form

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Q. $Cl_2$ reacts with $CS_2$ in presence of $I_2$ catalyst to form

The p-Block Elements - Part2

Solution:

$ CS_2 + 3Cl_2 \xrightarrow{I_2} CCl_4 + S_2Cl_2$