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Q.
Choose the correct statement with respect to the bond length of $CO$ and $CO^{+}$ :
NTA AbhyasNTA Abhyas 2022
Solution:
Because of the greater difference in electronegativity between $C$ and $O$, the energy of the molecular orbitals in CO are in the following order,
$\sigma_{1 s }^2 \sigma_{1 s }^{* 2} \sigma_{2 s }^2 \pi_{2 p _{ y }}^2=\pi_{2 p _{ z }}^2 \sigma_{2 p _{ z }}^2 \sigma_{2 s }^{* 2}$
Bond order in $CO =\frac{1}{2} 10-4=3$
When $CO$ is converted to $CO ^{+}$, one electron is removed from antibonding molecular orbitals. Hence, the bond order in $CO ^{+}$is greater than $CO$.