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  4. Chlorine reacts with sodium hydroxide under various conditions to give

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Q. Chlorine reacts with sodium hydroxide under various conditions to give

The p-Block Elements - Part2

Solution:

$\underset{\text{Cold, dilute}}{Cl_2 + 2NaOH} \underset{\text{sod. hypochlorite }}{ NaCl + NaCIO + H_2O }$
$\underset{\text{ hot cone }}{ 3Cl_2 + 6NaOH} \rightarrow \underset{\text{ sod. chlorate}}{5NaCl + NaClO_3 + 3H_2O }$
So sodium chloride is formed in both cases.