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  4. Chlorine is prepared in the laboratory by treating manganese dioxide (MnO2) with aqueous hydrochloric acid according to the reaction, 4HCl (aq) + MnO2(s)→ 2H2O(l) + MnCl2(aq) + Cl2(g) How many grams of HCl react with 5.0 g of manganese dioxide?

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Q. Chlorine is prepared in the laboratory by treating manganese dioxide $(MnO_2)$ with aqueous hydrochloric acid according to the reaction,
$4HCl _{(aq)} + MnO_{2(s)}\to 2H_2O_{(l)} + MnCl_{2(aq)} + Cl_{2(g)}$
How many grams of $HCl$ react with $5.0 \,g$ of manganese dioxide?

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Solution:

$\underset{\overset{4\,mol}{or 146\,g}}{4HCl_{(aq)}} + \underset{\overset{1 mol}{or 87\, g}}{MnO_{2(s)}} \to 2 H_2O_{(l)} + MnCl_{2(aq)} + Cl_{2(g)}$
$87 \,g$ of $MnO_2$ reacts with $146 \,g$ of $HCl$.
$\therefore 5\,g$ of $MnO_2$ will react with
$\frac{146 \times 5}{87} = 8.39 \approx 8. 40 \,g $ of $HCl$