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Q.
Chlorine exists in two isotopic forms, $Cl-37$ and $Cl-35$ but its atomic mass is $35.5$. This indicates the ratio of $Cl-37$ and $Cl-35$ is approximately
Structure of Atom
Solution:
Let relative abundance of $Cl-37 = x\%$
then relative abundance of $Cl-35 = (100 - x)\%$
Average atomic mass $=\frac{x \times 37+\left(100-x\right)35}{100}$
$=35.5$
$\Rightarrow 37x+3500-35x$
$=3550 \Rightarrow x=25$
$\therefore 100-x=75$
Thus, the ratio of $Cl-37$ and $Cl-35$ is $x$ : $(100 - x)$
$=25 : 75$
$1 : 3$