Question

Chemical $A$ when reacts with sodium carbonate forms compound $BandC$ . The solution turns milky on passing $CO_{2}$ from it. The chemical formula of $AandB$ are respectively:

• A. $NaOHandCa\left(\right.OH\left(\left.\right)_{2}$
• B. $Ca\left(\right.OH\left(\left.\right)_{2}andNaOH$
• C. $NaOHandCaO$
• D. $CaOandCa\left(\right.OH\left(\left.\right)_{2}$

Answer 1

Answer: (B)

$\underset{\left(\right. A \left.\right)}{C a \left(\right. O H \left.\right)_{2}} \, + \, \, Na_{2}CO_{3} \, \rightarrow \, \, \underset{\left(\right. B \left.\right)}{2 N a O H} \, + \, \underset{\left(\right. C \left.\right)}{C a C O_{3}} \\ \\ \underset{\left(\right. A \left.\right)}{C a \left(\right. O H \left.\right)_{2}}\overset{C O_{2}}{ \rightarrow }\underset{C \, \left(\right. m i l k y \left.\right)}{C a C O_{3}}$