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  4. CHCl3+C6H5NH2+3NaOH xrightarrow[]A+3B+3C In the above reaction, the product A is

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Q. $ CHC{{l}_{3}}+{{C}_{6}}{{H}_{5}}N{{H}_{2}}+3NaOH\xrightarrow[{}]{{}}A+3B+3C $ In the above reaction, the product A is

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Solution:

$ CHC{{l}_{3}}+{{C}_{6}}{{H}_{5}}N{{H}_{2}}+3NaOH\to $ $ \underset{phenylisocyanide}{\mathop{{{C}_{6}}{{H}_{5}}NC+3NaCl+3{{H}_{2}}O}}\, $