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  4. Charges -q and +q located at A and B, respectively, constitute an electric dipole. Distance AB = 2a, O is the mid point of the dipole and OP is perpendicular to AB. A charge Q is placed at P where OP = y and y >> 2a. The charge Q experiences and electrostatic force F. If Q is now moved along the equatorial line to P' such that OP' = ((y/3) ) , the force on Q will be close to: ((y/3) > > 2a)

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Q. Charges $-q$ and $+q$ located at $A$ and $B$, respectively, constitute an electric dipole. Distance $AB = 2a, O$ is the mid point of the dipole and $OP$ is perpendicular to $AB$. A charge $Q$ is placed at $P$ where $OP = y$ and $y >> 2a$. The charge $Q$ experiences and electrostatic force $F$. If $Q$ is now moved along the equatorial line to $P'$ such that $OP' = \left(\frac{y}{3} \right)$ , the force on $Q$ will be close to : $\left(\frac{y}{3} > > 2a\right)$Physics Question Image

JEE MainJEE Main 2019Electric Charges and Fields

Solution:

Electric field of equitorial plane of dipole
$= - \frac{K\vec{P}}{r^{3}} $
$ \therefore At P,F = \frac{K\vec{P}}{r^{3}} Q. $
$At P^{1} , F^{1} = - \frac{K\vec{P}Q}{\left(r/3\right)^{3}} = 27F $