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Q. Charge $Q$ is distributed to two different metallic spheres having radii $R$ and $2R$ such that both spheres have equal surface charge density, then charge on large sphere is

BITSATBITSAT 2019

Solution:

Let $q$ and $q'$ be the charges on spheres of radii $R$ and $2 R$ respectively.
Given $q+q'=Q$ ... (1)
Surface charge densities are
$\sigma=\frac{q}{4 \pi R^{2}}\,\,\sigma=\frac{q'}{4 \pi(2 R)^{2}}$
Given $\sigma=\sigma'$
$\therefore \frac{q}{4 \pi R^{2}}=\frac{q'}{4 \pi(2 R)^{2}}$
or $q'=4 q$
From eq (1) $q'=Q-q\,\,4 q=Q-q\,\,Q=5 q$ ...(2)
$q'=Q-q=Q-\frac{Q}{5}=\frac{4 Q}{5}$