1. Tardigrade
  2. Question
  3. Chemistry
  4. CH ≡ CH ->[HCl][ textExcess] A ->[ textHydrolysis][Δ] B ->[ textReduction][Na-Hg/H2O] C Compound C is

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Q. $ \ce{CH \equiv CH ->[HCl][\text{Excess}] A} $ $ \ce{->[\text{Hydrolysis}][\Delta] B} $ $ \ce{->[\text{Reduction}][Na-Hg/H_2O] C} $ Compound $ C $ is

MHT CETMHT CET 2011

Solution:

Correct answer is (c) ethanol

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