Question

$CH_3COOH\ce{->[NH_3]} \,\,\ce{->[\Delta]}$ ?
The product of the reaction is isomeric with

• A. $\underset{\overset{|}{N}H_2}{C}H_2-CHO$
• B. $CH_{3}CH=NOH$
• C. $HCONH-CH_{3}$
• D. All of these

Answer 1

Answer: (C)

$\ce{\underset{acetic\, acid}{CH3COOH} ->[NH_3]}\ce{CH3COONH4 ->[{\Delta}][{-H_2O}] CH3CO\underset{acetamide}{NH2}}$
The isomers of $CH _{3} CONH _{2}$ are
$NH _{2} \underset{(I)}{CH _{2}} CHO , CH _{3}- \underset{(II)}{CH} = NOH$,
$H - \underset{(III)}{CONH} - CH _{3}$