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Chemistry
CH3CH = CH2 xrightarrow[H2O2/OH-]BD3 product X Xis
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Q. $CH_3CH = CH_2\xrightarrow[H_2O_2/OH^-]{BD_3}$ product $X$ $X$is
Hydrocarbons
A
$CH_3-\underset{\overset{|}{O}H}{C}H -CH_2D$
22%
B
$CH_3-\underset{\overset{|}{D}}{C}H -CH_2OH$
43%
C
$CH_3-\underset{\overset{|}{O}D}{C}H -CH_3$
15%
D
None of these
20%
Solution:
$CH_3CH=CH_2\xrightarrow{BD_3}(CH_3-\underset{\overset{|}{D}}{C}H_2)_3B$
