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Chemistry
CH3CH2CH2C = CH xrightarrowBH3,THF xrightarrowH2O2/OH- 'X' Identify the product 'X' :
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Q. $CH_3CH_2CH_2C = CH \xrightarrow{BH_3,THF}\,\,\xrightarrow{H_2O_2/OH^-} 'X'$ Identify the product $'X'$ :
Hydrocarbons
A
$CH_3CH_2CH_2CH_2CHO$
22%
B
$CH_3CH_2CH_2\underset{\overset{||}{O}}{C}CH_2$
33%
C
$CH_3CH_2CH_2CHO$
11%
D
$CH_3CH_2\underset{\overset{||}{O}}{C}CH_2CH_3$
33%
Solution:
$CH_3 - CH_2 - CH_2 - C \equiv CH \xrightarrow[(2)H_2O_2/OH^-]{(1)BH_3-THF}$
