Question

$CH_3CH_2Br$ undergoes Wurtz reaction. We may expect some of the following product
$A : CH_3CH_2CH_2CH_3$
$B : CH_2 = CH_2$
$C : CH_3 — CH_3$
Select correct product.

• A. Only A
• B. A and B
• C. A, B and C
• D. A and C

Answer 1

Answer: (C)

$C_{2}H_{5}Br + Na^{•} \to CH_{3} CH_{2}^{•} + NaBr$
Intermediate free radical $CH_{3} CH_{2}^{•}$ combines to form $CH_{3}CH_{2} - CH_{2}CH_{3}$ (as amain product) and also $CH_{2} == CH_{2}$ and $C H_{3}CH_{3}$ by disproportion