Question

$CH_3 -\underset{\overset{|}{O}H}{CH} - CH_3 \ce{->[PBr_3]} \ce{->[H_2O]} D$ Here , $D$ is

• A. $CH_3 - \underset{\overset{|}{C}H_3}{CH} - O - CH_2 - CH_3$
• B. $CH_3 - O- \underset{\overset{|}{C}H_3}{CH} - CH_2 CH_3$
• C. $CH_3 - \underset{\overset{|}{C}H_3}{CH} - CH_2 CH_2OH$
• D. $CH_3 - CH_2- \underset{\overset{|}{C}H_3}{CH} - CH_2OH$

Answer 1

Answer: (C)

$CH_3 - \underset{\overset{|}{O}H}{CH} - CH_3 \ce{->[PBr_3]} \underset{(A)}{CH_3 - \underset{\overset{|}{B}r}{CH} - CH_3}$
$ \ce{->[Mg]} \underset{(B)}{CH_3 - \underset{\overset{|}{MgBr}}{CH} - CH_3}$
iso - pentylalcohol or $3$- methyl butane -$2$- ol