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  3. Chemistry
  4. CH3COOH ->[NH3] A ->[Δ] B ->[P2O5] C. C will be

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Q. $CH_{3}COOH \ce{ ->[NH_{3}] } \ce{A ->[\Delta] B} \ce{ ->[P_{2}O_{5}] } C$. $C$ will be

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Solution:

$CH_{3}COOH \ce{ ->[NH_{3}] }CH_{3}CO\overset{-}{O}NH^{+}_{4} \ce{ ->[Heat] }CH_{3}CONH_{2} \ce{ ->[P_{2}O_{5}] } \underset{\text{Methyl cyanide}}{{CH_{3}CN}}$