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  4. CH3Br xrightarrowKCNA xrightarrow [LiAlH4]4 [H]CH3CH2NH2 IUPAC name of textA is:

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Q. $CH_{3}Br\xrightarrow{KCN}A \xrightarrow [LiAlH_{4}]{4 \left[H\right]}CH_{3}CH_{2}NH_{2}$
IUPAC name of $\text{A}$ is:

NTA AbhyasNTA Abhyas 2022

Solution:

$CH_{3}Br\xrightarrow{KCN} \underset{\text{Ethane nitrile}}{CH_{3} CN} \xrightarrow [LiAlH_{4}]{4 \left[H\right]}\underset{\text{Ethylamine}}{CH_{3} CH_{2} NH_{2}}$
IUPAC name of compound A (acetonitrile) is Ethane nitrile.
Methyl bromide reacts with pottasium cyanide to produce acetonitrile which on reduction with Lithium aluminium hydride (LAH) produces primary amine (Propan-1-amine).
Alkyl halides are characterised by nucleophilic substitution reaction followed by reduction reaction.