Question

$(CH_3)_2 CO \xrightarrow[{(HCl)}]{{NaCN}} A \xrightarrow{{H_3O^+}} B $
In the above sequence of reactions $A$ and $B $ are

• A. $\left( CH _{3}\right)_{2} C ( OH ) CN ,\left( CH _{3}\right)_{2} C ( OH ) COOH$
• B. $\left( CH _{3}\right)_{2} C ( OH ) CN ,\left( CH _{3}\right)_{2} C ( OH )_{2}$
• C. $\left( CH _{3}\right)_{2} C ( OH ) CN ,\left( CH _{3}\right)_{2} CHCOOH$
• D. $\left( CH _{3}\right)_{2} C ( OH ) CN ,\left( CH _{3}\right)_{2} C =O$

Answer 1

Answer: (A)

Correct answer is (a) $\left( CH _{3}\right)_{2} C ( OH ) CN ,\left( CH _{3}\right)_{2} C ( OH ) COOH$